Question

A warehouse employs 26 workers on first​ shift, 18 workers on second​ shift, and 13 workers on third shift. Eight workers are chosen at random to be interviewed about the work environment. Find the probability of choosing exactly four third​-shift workers. The probability of choosing exactly four third​-shift workers is nothing. ​(Round to three decimal places as​ needed.)

Please explain how you get everything, thanks

Answer 1

1) probability of choosing exactly four third​-shift workers =P(selecting 4 from 13 of 3rd shift workers and 4 from remaining 44 workers)= ¹³C₄*⁴⁴C₄/⁵⁷C₈ =715*135751/1652411475 =0.059