Question

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#Recall in an earlier problem you were given two lists: one
#list was a student's answers to a test, and the other was
#the answer key. Your goal was to return a score
#representing the number of problems the student got correct.
#
#Let's do that again, but with dictionaries instead of lists.
#Write a function called calculate_score. calculate_score
#should take two parameters: a dictionary of student answers
#and a dictionary of correct answers. Both dictionaries should
#have integers as their keys, and one-character strings as
#their values.
#
#calculate_score should count how many questions the student
#got right. Or, in more precise terms, calculate_score should
#count how many keys for which the associated value is the
#same in the student's dictionary and in the answer key
#dictionary.
#
#As before, it is possible that there will be more answers in
#one than the other. This means that these answers don't
#belong to the same test! If that happens, return -1.

#Add your function here!

#Below are some lines of code that will test your function.
#You can change the value of the variable(s) to test your
#function with different inputs.
#
#If your function works correctly, this will originally
#print: 3
student_answers = {1: "A", 2: "B", 3: "C", 4: "D", 5: "E"}
correct_answers = {1: "A", 2: "B", 3: "A", 4: "D", 5: "B"}
print(calculate_score(student_answers, correct_answers))

Answer 1

# Recall in an earlier problem you were given two lists: one
# list was a student's answers to a test, and the other was
# the answer key. Your goal was to return a score
# representing the number of problems the student got correct.
#
# Let's do that again, but with dictionaries instead of lists.
# Write a function called calculate_score. calculate_score
# should take two parameters: a dictionary of student answers
# and a dictionary of correct answers. Both dictionaries should
# have integers as their keys, and one-character strings as
# their values.
#
# calculate_score should count how many questions the student
# got right. Or, in more precise terms, calculate_score should
# count how many keys for which the associated value is the
# same in the student's dictionary and in the answer key
# dictionary.
#
# As before, it is possible that there will be more answers in
# one than the other. This means that these answers don't
# belong to the same test! If that happens, return -1.

def calculate_score(student, correct):
    count = 0
    for k, v in student.items():
        if correct[k] == v:
            count += 1
    return count


# Below are some lines of code that will test your function.
# You can change the value of the variable(s) to test your
# function with different inputs.
#
# If your function works correctly, this will originally
# print: 3
student_answers = {1: "A", 2: "B", 3: "C", 4: "D", 5: "E"}
correct_answers = {1: "A", 2: "B", 3: "A", 4: "D", 5: "B"}
print(calculate_score(student_answers, correct_answers))