Question

Sulfuric acid can dissolve aluminum metal according to the following reaction. 2Al(s)+3H2SO4(aq)→Al2(SO4)3(aq)+3H2(g)Suppose you wanted to dissolve an aluminum block with a mass of 28.5 g .

Part A What minimum amount of H2SO4 in grams would you need? m m = nothing   g   SubmitRequest Answer Part B How many grams of H2 gas would be produced by the complete reaction of the aluminum block?

Answer 1

2Al (s) + 3H₂SO₄ (aq) → Al₂(SO₄)₃ (aq) + 3H₂ (g)

Part A: What minimum amount of H₂SO₄ in grams would you need ?

Solution:

(28.5 g Al) / (26.982 g/mole Al) x (3 mole H₂SO₄ / 2 mole Al) x (98.08 g /1 mole H₂SO₄) = 155.4 g H₂SO₄

Part B: How many grams of H₂ gas would be produced by the complete reaction of the aluminum block?

Solution:

(28.5 g Al) / (26.982 g/mole Al) x (3 mole H₂ / 2 mole Al) x (2.016 g H₂/1 mole H₂) = 3.19 g H₂