Question

A coil of wire has a resistance of 53.6Ω at 29 °C and 61.0Ω at 48 °C. What is the temperature coefficient of resistivity? Please show work. Thank you.

Answer 1

here,

for T1 = 29 degree C , R1 = 53.6 ohm

for T2 = 48 degree C , R2 = 61 ohm

the temp. coeff. of resistivity , alpha = (R2 - R1) / (R1 * t2 - R2 * t1 )

alpha = ( 61 - 53.6) /( 53.6 * 48 - 29 * 61)

alpha = 0.0092 per degree C

the temp. coeff. of resistivity is 0.0092 per degree C