Marks on an anatomy assignment follow a normal distribution with a mean of 65 and a standard deviation of 12. Approximately what percentage of the students have scores below 50?
Select one:
a. 39%
b. 11%
c. 18%
d. 15%
e. 89%
Solution :
Given that,
mean =
= 65
standard deviation =
= 12
P(X< 50) = P[(X-
) /
< (50-65) / 12]
= P(z < -1.25)
Using z table
= 0.1056
answer=11%
Marks on an anatomy assignment follow a normal distribution with a mean of 65 and a...