yes that is the reaction we actually take here .if sodium chloroacetate is not given then ClCH2COO- ion concentration comes from only CA. if it is given then the ClCH2COO- ion concentration comes from CA is very less compared to direct concentration given . so we need not count from CA
let us see through ice table:
1) without common ion :
ClCH2COOH + H2O -----------------> H3O+ + ClCH2COO-
0.20 0 0 ---------------> I
-x +x +x ----------------------> C
0.20 -x x x -------------------> E
2) with common ion :
ClCH2COOH + H2O -----------------> H3O+ + ClCH2COO-
0.20 0 0.10 ---------------> I
-x +x +x ----------------------> C
0.20 -x x 0.10 + x -------------------> E
here we can use now HH equation .
pH = pKa + log [ClCH2COO- / ClCH2COOH]
pH = 2.85 + log (0.10 / 0.20)
pH = 2.55
What is the pH of a buffer that is 0.200 M chloroacetic acid and 0.100 M...