Question

How can I convert decimal number 287 to hex by using loops? not using hex function

Answer 1

#include <stdio.h>

#include <string.h>

void ReverseDigits(char *arr)

{

int i = 0 , j = strlen(arr)-1;

while(i<j)

{

char temp = arr[i];

arr[i] = arr[j];

arr[j] = temp;

++i;

--j;

}

}

int main()

{

int d , r, i = 0, num;

printf("Enter a number: ");

scanf("%d", &d);

r = 16;

num = d;

char output[100];

while (d > 0)

{

int val = d % r;

if(val>=0 && val<=9)

output[i++] = (char)(val + '0');

else

output[i++] = (char)(val - 10 + 'A');

d = d/r;

}

output[i] = '\0';

ReverseDigits(output);

printf("The number %d in base %d is %s\n", num, r, output);

return 0;

}

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SEE OUTPUT


Thanks, PLEASE COMMENT if there is any concern.