Give a context-free grammar (CFG) that generates the language L = { a⁽ʲ⁺ᵏ⁾bc⁽ʲ⁺ᵗ⁾de⁽ᵏ⁺ᵗ⁾ : j,k,t ≥ 0 }
The language to generate is
. The idea here is that the start symbol first generated some equal
number a's and e's. Then it goes to two symbols, one which produces
and the other
which produces
. It helps to
think of the language as
. Hence, the start symbol produces the outer strings, while A and B
produce the strings inside the parantheses. Here is the
grammar:

Comment in case of any doubts.
Give a context-free grammar (CFG) that generates the language L = { a⁽ʲ⁺ᵏ⁾bc⁽ʲ⁺ᵗ⁾de⁽ᵏ⁺ᵗ⁾ : j,k,t ≥...