Question

Motion of the rocket is given by the following equation:

x=1+1t+7t²+2t³ where t is in seconds, x is in meters.

At 14s a small object detaches itself from the body of the rocket.

What is the initial height of this object?

Round your answer to the nearest tenth of a m.

Answer 1

x(t) = 1 + t + 7t² +2t³

At t = 14 s position of rocket will be

x(t=14) = 1 + 14 + 7(14)² +2(14)³

x (t=14s) = 6,875

So, As object detaches from rocket, its initial position will also be x = 6.875 m

Digit to the right of tenth is 5. So increase tenth by 1 and make digits to the right of tenth zero.

So Our answer to the nearest tenth is 6,880 m.