Question

assume that a procedure yields a binomial distribution with a trial repeated n=7 times. use the binomial probability formula to find the probability of k=3 success given the probability p=0.79 success on a single trial.

Answer 1

Let X be the binomial random variable that denotes the number of successful events, n be the total number of times the trial is done, p be the probability of success and q be the probability of failure. Then

Here,

n=7, k=3, p=0.79, q=0.21

Therefore,