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A force of 2.30×104 NN is applied to a diver's face mask that has an area of 115 cm2cm2 . |
Part A Find the pressure in atmatm on the face mask. (1 atmatm = 101,325 PaPa) Express your answer with the appropriate units. |
we have
F = 2.30 * 10^4 N
and
A = 115 cem^2 = 115 * (0.01)^2 = 0.0115 m^2
we know,
P = F / A
or
P = 2.30 * 10^4 / 0.0115 = 2.0 * 10^6 N / m^2 = 2.0 * 10^6 Pa = 2000 KPa = 2000 / 101.325 = 19.7 atm
thus
pressure = 19.7 atm
A force of 2.30×104 NN is applied to a diver's face mask that has an area...