Question

What is the electronic configuration for the ion formed when boron loses three electrons.

Express your answer in complete form, in order of increasing orbital energy. For example, 1s22s2 would be entered as 1s^22s^2.

Answer 1

Boron

Atomic number is 5 so it has 5 electrons

When boron loses three electrons it becomes B^3+ and it has just two electrons which equals Helium (He)

So it's electron configuration is 1s^2