If 23.8 g of NO and 13.8 g of O₂ are used to form NO₂, how many moles of excess reactant will be left over? 2 NO (g) + O₂ (g) → 2 NO₂ (g)
If 23.8 g of NO and 13.8 g of O₂ are used to form NO₂, how...
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