Question

Find the value of the probability of the standard normal random variable Z corresponding to this area. (Round your answer to four decimal places.)

P(0.86 < Z < 2.02) =

Answer 1

P(0.86 < Z < 2.02) = P(Z < 2.02) - P(Z < 0.86)

= 0.9783 - 0.8051 (From Z table)

= 0.1732