Question

Could I get some help with this data structure to consider the following method with integer value x.

public static test(int x)

{

x += 2;

}

Suppose y has a value of 10, then the method is activated test(y) what is the value of y after this activation?

Answer 1

Answer: 12

Explanation:

The statement x+=2; works like x=x+2;

As you asked if we initialize y with 10 y=10

and called test(y);

then y = y+2;

Therefore y =12;

In coding form:

public class Tester2 {

     

      public static void main(String[] args) {

            // TODO Auto-generated method stub

            //Initializing y with 10

            int y= 10;

            //calling the test function

            System.out.println("value of y before calling test: "+y);

            y= test (y);

            //printing the value of y after test activation

            System.out.println("value of y after calling test: "+y);

      }

      public static int test(int x) {

            // TODO Auto-generated method stub

            x += 2;

            return x;

      }

}

Output: