Question

fool's gold is so called because it bears a visual similarity to real gold. a block of fool's old which measures 1.50 cm by 2.50 cm by 3.00 cm has a mass of 56.25g. how can this material be distinguished from real gold by means of physical properties. show a calculation to prove your point. chemistry

Answer 1

The volume of fool's gold = 1.50 cm x 2.50 cm x 3.00 cm = 11.25 cm³

The mass of the block of fool's gold = 56.25 g

Determine the density of the real gold as follows:

The formula to determine the density is as follows:

Density = Mass / Volume

Substitute 56.25 g for mass and 11.25 cm³ for volume. Determine the density of the fool's gold as follows:

Density = 56.25 g / 11.25 cm³

Density = 5 g/cm³

Thus, the density of the fool's gold is 5 g/cm³.

The density of the real gold = 19.3 g/cm³

Since the density of fool's gold and the real gold vary with a very large number. The fool's gold is not a bar of real gold.