Question

0.10 mol of argon gas is admitted to an evacuated 44 cm3 container at 20∘C. The gas then undergoes an isobaric heating to a temperature of 290 ∘C.

What is the final volume of the gas?

Express your answer to two significant figures and include the appropriate units.

Answer 1

Given:

Number of mole, n = 0.10 mol

Initial volume, V1 = 44 cm3

Initial temperature, T1 = 20℃ = 293.15 K

Final temperature, T2 = 290℃ = 563.15 K

Final volume, V2 = ? (To find)

Process is isobaric, so pressure will remain same in the process.

In isobaric process, nRT/V will remain constant.

So, V2 = 85 cm3