Consider the following regression results based on 20 observations. [You may find it useful to reference the t table.]
| Coefficients | Standard Error | t Stat | p-value | |
| Intercept | 31.4171 | 4.4496 | 7.061 | 0.000 |
| x1 | 0.1629 | 0.1944 | 0.838 | 0.413 |
a-1. Choose the hypotheses to determine if the intercept differs from zero.
H0: β0 ≥ 0; HA: β0 < 0
H0: β0 = 0; HA: β0 ≠ 0
H0: β0 ≤ 0; HA: β0 > 0
a-2. At the 5% significance level, what is the
conclusion to the hypothesis test? Does the intercept differ from
zero?
Reject H0; the intercept is greater than zero.
Reject H0; the intercept differs from zero.
Do not reject H0; the intercept is greater than zero.
Do not reject H0; the intercept differs from zero.
b-1. Construct the 95% confidence interval for the slope coefficient. (Negative values should be indicated by a minus sign. Round "tα/2,df" value to 3 decimal places and final answers to 2 decimal places.)
Confidence interval _____ to ______?
b-2. At the 5% significance level, can we conclude the slope differs from zero?
Yes, since the interval contains zero.
Yes, since the interval does not contain zero.
No, since the interval contains zero.
No, since the interval does not contain zero.
a-1. Null and alternative hypothesis:
H0: β0 = 0; HA: β0 ≠ 0
a-2. p-value = 0.000
Reject H0; the intercept differs from zero.
b-1. 95% confidence interval for the slope coefficient.
Critical value, t_c = T.INV.2T(0.05, 18) = 2.1009
95% Confidence interval for slope:
Lower limit = b1 - tc*se(b1) = 0.1629 - 2.1009*0.1944 = -0.25
Upper limit = b1 + tc*se(b1) = 0.1629 + 2.1009*0.1944 = 0.57
b-2. No, since the interval contains zero.
Consider the following regression results based on 20 observations. [You may find it useful to reference...