Question

When excess Ag metal is added to 0.200 L of 1.240 M Fe3+(aq) at 298K, the following equilibrium is established: Ag+(aq) + Fe2+(aq) Ag(s) + Fe3+(aq)

(1) If the equilibrium concentration of Ag+ is 0.501 M, what is the value of K? K =

(2) Using the value of K from part (1), calculate the new equilibrium concentrations of the three species in solution, if the volume of the solution is increased to 0.650 L by the addition of pure water?

[Ag+] =

[Fe2+] =

[Fe3+] =

Answer 1