Question

Write a Python function that displays a one-year calendar for any year. The program should prompt the user for a year (past, present or future). Then the program should calculate, the weekday for Jan 1 for that year. there is an equation for calculating this value, which is given as: day = R(1+5R(Y-1,4)+4(Y-1,100)+6R(Y-1,400),7) R(x,y) is remainder after the division of x by y, and Y is the year. The equation produces a value between 0 and 6, where 0 is Sunday, 1 is Monday,….6 is Saturday.

I am having trouble implementing this equation correctly in Python3. I am wondering how I would write this. Thanks

Answer 1

If you have any doubts, please give me comment...

months = ["January", "February", "March", "April", "May", "June", "July", "August", "September", "October", "November", "December"]

dayNames = ["Sun", "Mon", "Tue", "Wed", "Thu", "Fri", "Sat"]

days = [31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31]

Y = int(input("Enter year: "))

day = (1+5*((Y-1)%4)+4*((Y-1)%100)+6*((Y-1)%400))%7

if (((Y % 4 == 0) and (Y % 100 != 0)) or (Y % 400 == 0)):

    days[1] += 1

for i in range(12):

    print("\t"+months[i]+", "+str(Y))

    for j in range(7):

        print("%3s"%dayNames[j], end=' ')

    print()

    print('    '*day, end='')

    for j in range(1, days[i]+1):

        print("%3d"%j, end=' ')

        if (j+day)%7==0:

            print()

    print("\n")