Question

A strip of copper 170 µm thick and 4.70 mm wide is placed in a uniform magnetic field of magnitude B = 0.75 T, that is perpendicular to the strip. A current i = 18 A is then sent through the strip such that a Hall potential difference V appears across the width. Calculate V. (The number of charge carriers per unit volume for copper is 8.47 × 10²⁸ electrons/m³.)

Number

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Units

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IE

Answer 1

Solution,

Potential, V = BI/ e n L

V = (0.75 x 18)/(8.47 x 10^28 x 170 x 10^-6 x 1.6 x 10^-19)

V = 5.86 x 10^-6 V

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