Plot the following function on MATLAB h(t) = cos(pi*t/2) -2 <= t < -1 1 +...

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Question

Plot the following function on MATLAB h(t) = cos(pi*t/2) -2 <= t < -1 1 +...

Plot the following function on MATLAB

h(t) = cos(pi*t/2) -2 <= t < -1

1 + t³ -1 <= t < 0

1 0 <= t < 1

1 + sin(2*pi*t) 1 <= t < 2

0 elsewhere

engineering Electrical-Engineering

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Answer 1

Answer #1

%MATLAB CODE
fplot(@(t)cos(pi*t/2),[-2 -1],'b')
hold on
fplot(@(t)(1+t^3),[-1 0],'b')
hold on
fplot(@(t)1,[0 1],'b')
hold on
fplot(@(t)(1+sin(2*pi*t)),[1 2],'b')
hold off
grid on

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Answer 2

Plot the following function on MATLAB h(t) = cos(pi*t/2) -2 <= t < -1 1 +...

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Plot the following function on MATLAB h(t) = cos(pi*t/2) -2 <= t < -1 1 +...

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Add Answer to: Plot the following function on MATLAB h(t) = cos(pi*t/2) -2 <= t < -1 1 +...

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Plot the following function on MATLAB h(t) = cos(pi*t/2) -2 <= t < -1 1 +...