Assume the hours spent watching tv for a population is 4 hours
and the standard deviation is 1.5 hour. The population is
approximately normally distributed.
What z-score corresponds to the 44th percentile? Round to 2 decimal
places.
The bottom 44% of people watch at most how many hours of television? Round to 2 decimal places.
Given that,
mean =
= 4
standard deviation =
= 1.5
Using standard normal table,
P(Z < z) = 44%
= P(Z < z) = 0.44
z = -0.15 Using standard normal z table,
Using z-score formula
x= z *
+
x= -0.15 *1.5+4
x= 3.78
Assume the hours spent watching tv for a population is 4 hours and the standard deviation...