Calculate how many grams of sodium acetate are needed to make 100.0 ml of acetic acid/sodium acetate buffer with the pH of 5.00 using 0.100 M acetic acid and solid sodium acetate.
PH = 5
PKa = 4.75
no of moles of CH3COOH = molarity * volume in L
= 0.1*0.1 = 0.01moles
PH = Pka + log[CH3COONa]/[CH3COOH]
5 = 4.75 + log[CH3COONa]/0.01
log[CH3COOH]/0.01 = 5-4.75
log[CH3COONa]/0.01 = 0.25
[CH3COONa]/0.01 = 10^0.25
[CH3COONa]/0.01 = 1.7783
[CH3COONa] = 1.7783*0.01
[CH3COONa] = 0.017783 moles
mass of CH3COOH = no of moles * gram molar mass
= 0.017783 *82 = 1,46g >>>>answer
Calculate how many grams of sodium acetate are needed to make 100.0 ml of acetic acid/sodium...