A light ray leaves point A in the figure, reflects from the mirror, and reaches point B.
A light ray leaves point A in Figure 1, reflects from the mirror, and reaches point B. How far below the top edge does the ray strike the mirror? What if the distance from point B to the mirror was reduced by 5 cm?
Homework Answers
The incident and reflected light rays will form two right angled triangles as shownFrom the laws of reflection,the angle of incidence = the angle of reflectionx / 10 cm = (10 cm - x) / 15 cm15 x = 100 - 10x25x = 100x = 4 cmTherefore the light ray will strike the mirror at 9 cm below the top edge
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A light ray leaves point A in the figure, reflects from the mirror, and reaches point B.
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are A=(10.5, 15.1) and B=(15.9, 4.9), in centimetres.
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Here is a figure that shows a light ray that is H=23cm parallel
to and above the ground.
The light ray goes through a medium with an index of refraction
of n1=1.2, and some of it reflects and some of it
refracts.
The refracting part goes into a medium with an index of
refraction of n2=1.5.
If the angle ? = 30 degrees:
What is the distance between point A and point B (in
cm)?
What is the angle between...
3. A ray of light is reflected from two plane mirror surfaces as shown in the figure. What are the correct values of α and β? 26° 얘) Value of a-? Value of B7
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