Question

In the theory of relativity, the mass of a particle with velocity v is m=mo/(square root ((1- v^ 2)/ c^2)) where mo is the mass of the particle at rest and ci s the speed of light

In the theory of relativity, the mass of a particle with velocity v is

m=mo/(square root ((1- v^ 2)/ c^2))

where mo is the mass of the particle at rest and ci s the speed of light. What happens as v goes to c?
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Answer #1
i meant
what happens as v goes to c-
answered by: Arrie
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Answer #2
as v goes to c, v^2 becomes c^2 and c^2/c^2 = 1,, therefore m becomes mo/sqrt(1-1) or mo/0 which is undefined,,
according to this, no such thing can exist with speed equal to the speed of light,,

so there,, =)
answered by: baasima
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In the theory of relativity, the mass of a particle with velocity v is m=mo/(square root ((1- v^ 2)/ c^2)) where mo is the mass of the particle at rest and ci s the speed of light
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