Balance the following reaction in acidic solution:
As2O3 (s) + NO3-(aq) → H3AsO4 (aq) + NO (g)

The answer is:
(d) 7 H2O + 4 H+ + 3 As2O3 + 4 NO3- => 4 NO + 6 H3As3O4
Half-reaction:
Oxidation: 3 As2O3 + 15 H2O => 6 H3As3O4 + 12 H+ + 12 e-
Reduction: 4 NO3- + 16 H+ + 12 e- => 4 NO + 8 H2O
Add Oxidation + Reduction:
3 As2O3 + 15 H2O + 4 NO3- + 16 H+ + 12 e-
=> 6 H3As3O4 + 12 H+ + 12 e- + 4 NO + 8 H2O
Cancel common terms to get overall balanced equation:
7 H2O + 4 H+ + 3 As2O3 + 4 NO3- => 4 NO + 6 H3As3O4
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