Question

what is the probability of drawing 3 clubs or a six of diamonds?

Answer 1

what is the probability of drawing 3 clubs or a six of diamonds? ------------------- Those are mutually exclusive events so P(3 clubs or six of diamonds) = P(3clubs)+P(6 of diamonds) = 13C3/52C3 + 1/52 = 286/22100 + 1/52 = 0.13 + 0.19 = 0.32 ============ Cheers, Stan H.

Answer 2

I'm assuming you mean a standard 52 card deck and your question is the probability of drawing either a 3 Clubs{{{P[1]}}} or 6 Diamonds {{{P[2]}}}on one draw. The probability of drawing a 3 Clubs alone and the probability of drawing a 6 Diamonds alone are both equal{{{P[1]=P[2]=1/52}}}. By putting them together, you add their probabilities. So the probability of drawing either a 3 Clubs or 6 Diamonds on one draw is 2/52{{{P[3]=1/52+1/52=2/52}}}.