Impure sample of table salt that weighed 0.8421g, when dissolved in water and treated with excess AgNO3, formed 2.044g of AgCl
Do I need the molecular weight to start this equation? Where do I start?
Homework Answers
%NaC= (mass NaCl/mass sample)*100
mass sample = 0.8241 g.
mass AgCl = 2.044 g
moles AgCl = g/molar mass = ??
moles Cl is the same as moles AgCl. moles NaCl is same as mols AgCl.
moles NaCl x molar mass NaCl = mass NaCl.
Substitute into the top equation and solve for %NaCl.
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Impure sample of table salt that weighed 0.8421g, when dissolved in water and treated with excess AgNO3, formed 2.044g of AgCl
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