Question

If 10.00 g of ammonia react, how many moles of fertilizer will be produced?

(NH4)2HPO4 is made from reacting phosphoric acid, H3PO4
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Answer #1

This problem asks about the reaction of ammonium hydrogen phosphate, , which is produced from a reaction between two components: phosphoric acid, , and ammonia, .

a.

Part a. asks you to write the balanced equation for the reaction. By performing a mass balance on the individual elements of the reactants and product, you can determine that the balanced equation will require 2 moles of ammonia to 1 mole of each of the other components, written below.

b.

Part b. asks for the number of moles of ammonium hydrogen phosphate that will be produced from the reaction of 10.00 grams () of ammonia. To solve this problem, first convert the number of grams of ammonia to moles by dividing by its molar mass. Next, multiply the number of moles of ammonia by the stoichiometric ratio of ammonium hydrogen phosphate to ammonia to find the number of moles of ammonium hydrogen phosphate produced.

So, 0.2390 moles of ammonium hydrogen phosphate will be produced from the reaction of 10.00 grams () of ammonia.

c.

Part b. asks for the mass of ammonia in kilograms () that will be produced from the reaction of 2800 kilograms () of phosphoric acid. To solve this problem, first convert the number of kilograms () of phosphoric acid to moles by dividing by its molar mass. Next, multiply the number of moles of phosphoric acid by the stoichiometric ratio of phosphoric acid to ammonia to find the number of moles of phosphoric acid. Finally, convert the number of moles of ammonia to the mass of ammonia by multiplying by its molar mass.

So, 970 kilograms () of ammonia will be produced from the reaction of 2800 kilograms () of phosphoric acid.

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