a flowerpot falls from a windowsill 25.0 m above the sidewalk. How fast is the flowerpot moving...

Question

Question

a flowerpot falls from a windowsill 25.0 m above the sidewalk. How fast is the flowerpot moving when it strikes the ground?

science physics

Answer 1

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Answer #1

x(t) = 1/2*a*t^2

-25 = -4.9t^2

t = 2.2587

v = at + v0

v(2.2587) = -9.8*2.2587 = -22.135 m/s <ANSWER

PLEASE RATE.

answered by: Rosh

Answer 2

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