Estimate the enthalpy of formation of HBr gas.
H2(g) + Br2(g) --> 2HBr(g)
H-H bond = 436 kJ/mol
Br-Br bond = 192 kJ/mol
H-Br bond = 366 kJ/mol


The enthalpy of formation of the reaction is 104 kJ/mol.
ΔH° = Σ(v × ΔHf°) (products) - Σ(v × ΔHf°) (reactants)
2x366 - 192 -436 = 104 kJ/mol
Use bond energies to estimate the enthalpy of formation of HBr(g). BE(H–H) = 436 kJ/mol BE(Br–Br) = 192 kJ/mol BE(H–Br) = 366 kJ/mol A –52 kJ/mol B +262 kJ/mol C +104 kJ/mol D +52 kJ/mol E –104 kJ/mol
A Reaction is given: ½Br2(l) --> Br(g) Ho = 112kJ/mol The bond enthalpy of Br-Br is 193 kJ/mol A. Formulate the vaporization process of 1 mol bromine Br2(l). B. Calculate the enthalpy of the vaporization process bromine. Show calculations C. Calculate the energy invested \ emitted by the evaporation of 3.2 gr of bromine. Show calculations. (Explain how you determined whether the energy is invested or emitted in this process). D.A Reaction is given: ½H2(g) + ½Br2(l) --> HBr(g) Ho...
Use the bond enthalpy data given to estimate the enthalpy of reaction for the addition of HBr to acetylene gas, C2H2 to form C2H4Br2 (with the condensed structural formula Br-CH2-CH2-Br ) at 25°C. BE(C-C) = 348 kJ/mol; BE(CC triple bond) = 839 kJ/mol; BE(C-H) = 413 kJ/mol; BE(H-Br) = 366 kJ/mol; BE(C-Br) = 276 kJ/mol -581 kJ/mol -4949 kJ/mol +155 kJ/mol -887 kJ/mol +887 kJ/mol
Calculate the enthalpy of formation of the anhydrous salt of aluminum bromide (AlBr 3) using the following data: 2Al (s) + 6HBr (aq) → 2AlBr3 (aq) + 3H2 (g) Δ? = -1061 kJ mol-1 HBr (g) → HBr (aq)∆? = -81.15 kJ mol-1 H 2 (g) + Br2 (l) → 2HBr (g) Δ? = -72.80 kJ mol-1 AlBr 3 (s) → AlBr 3 (aq)∆? = -368 kJ mol-1
If Delta H for the following reaction is -36.40 kJ/mol, what is the enthalpy of formation of HBr(g)? 1/2 H2 (g)+1/2 Br2 --->HBr(g)
A scientist measures the standard enthalpy change for the following reaction to be -77.5 kJ: 2HBr(g) + Cl2(g) 2HCl(g) + Br2(g) Based on this value and the standard enthalpies of formation for the other substances, the standard enthalpy of formation of HBr(g) is kJ/mol.
Estimate the enthalpy of formation of HF from the following bond energies: (twenty-five points) H2 (g) + F2 (g) → 2 HF (g) Bond: H-H =432KJ/mol F-F=159 KJ/mol H-F= -565 KJ/mol
Estimate the enthaply of formation, Delta Hf, of hydrogen peroxide, H2O2(g), From the relevant bond enthalpy data provided Bond Enthaplies in KJ mol-1 O=O 498 O-O 138 H-H 436 O-H 464 A) -132 KJ MOL -1 B) -87 KJ MOL-1 C) -69.4 Kj mol -1 D) 45.8 Kj mol-1 E) 156 Kj mol -1
The enthalpy change for the following reaction is 95.4 kJ. Using bond energies, estimate the N-H bond energy in N2H4(g). N2(g) + 2H2(g) N2H4(g) kJ/mol The enthalpy change for the following reaction is -92.2 kJ. Using bond energies, estimate the H-H bond energy in H2(g). 2NH3(g) N2(g) + 3H2(g) kJ/mol D Single Bonds Multiple Bonds C N O F Si P S a Br 1 H 436 413 391 463 565 318 322 347 C 413 346 305 358 485...
Part A. Find the average enthalpy of the PF bond in PF5(g) from
the following standard molar enthalpies of formation (in kJ/mol):
PF5(g) (–1595), P(g) (315), F(g) (79).
Part B.
Using the bond energies from the table below estimate AH for the following reaction C2H2(g) + H2(g) → C2H4(g) Bond Bond energy [kJ/mol] [C-H 413 H-H 436 |C-C 348 C=C 614 csc 839