help. easy one
the answer comes out to 10.4 m/s^2
pls show all formulas and steps used
thanks :)
Homework Answers
if pevious time period = T1
the T2=(1-3.2/100)T1= .968T1
we know g2/g1=(T1/T2)^2= (1/.968)^2
so g2= 9.8/ (.968)^2= 10.46 m/s^2
When a pendulum with a period of 2.00000 s is moved to a new location from...
When a pendulum with a period of 2.00000 s is moved to a new location from one where the acceleration due to gravity was 9.80 m/s2, its new period becomes 1.99900 s. By how much does the acceleration due to gravity differ at its new location? Incorrect: Your answer is incorrect. How is the period of the pendulum related to the length of the pendulum and the acceleration due to gravity at the location of the pendulum? What happens to...
When a pendulum with a period of 2.00000 s in one location (g = 9.80 m/s2)...
When a pendulum with a period of 2.00000 s in one location (g = 9.80 m/s2) is moved to a new location from one where the period is now 1.99869 s. What is the change in acceleration (in m/s2) due to gravity at its new location?
When a pendulum with a period of 2.00000 s in one location (g = 9.80 m/s)...
When a pendulum with a period of 2.00000 s in one location (g = 9.80 m/s) is moved to a new location from one where the period is now 1.99844 s. What is the change in acceleration (in m/s2) due to gravity at its new location?
When a pendulum with a period of 2.00000 s in one location (g = 9.80 m/s2)...
When a pendulum with a period of 2.00000 s in one location (g = 9.80 m/s2) is moved to a new location from one where the period is now 1.99808 s. What is the change in acceleration in m/s) due to gravity at its new location? m/s²
(a) What is the length of a simple pendulum that oscillates with a period of 2.6...
(a) What is the length of a simple pendulum that oscillates with a period of 2.6 s on Earth, where the acceleration due to gravity is 9.80 m/s2, and on Mars, where the acceleration due to gravity is 3.70 m/s2? LE = LM = Enter a number. Im (b) What mass would you need to suspend from a spring with a force constant of 20 N/m in order for the mass-spring system to oscillate with a period of 2.6 s...
(a) What is the length of a simple pendulum that oscillates with a period of 3.0...
(a) What is the length of a simple pendulum that oscillates with a period of 3.0 s on Earth, where the acceleration due to gravity is 9.80 m/s2, and on Mars, where the acceleration due to gravity is 3.70 m/s2? LE = Lм %3 m (b) What mass would you need to suspend from a spring with a force constant of 20 N/m in order for the mass-spring system to oscillate with a period of 3.0 s on Earth, where...
13.11 A pendulum has a length of 4.8 m. a) At a location where the acceleration...
13.11 A pendulum has a length of 4.8 m. a) At a location where the acceleration due to gravity is 9.80 m/s, what is the period of the pendulum? b) If the period of a pendulum is twice as much the value found in part a, what is the length?
I need help with these three problems pls. show steps and formulas pls thanks. 13. A...
I need help with these three
problems pls. show steps and formulas pls thanks.
13. A 119 g mass is attached to the end of an unstressed vertical spring (of constant 52.5 N/m) and then dropped. The acceleration of gravity is 9.8 m/s2 What is its maximum speed? Correct answer: 0.466573 m/s. 14. A(n) 60.3 g ball is dropped from a height of 53.7 cm above a spring of negligible mass. The ball compresses the spring to a maximum displacement...
The period T of a simple pendulum is given by T=2πLg−−√T=2πLg where L is the length of the...
The period T of a simple pendulum is given by T=2πLg−−√T=2πLg where L is the length of the pendulum and g is the acceleration due to gravity. Assume that g = 9.80 m/s2 exactly, and that L, in meters, is lognormal with parameters μL = 0.8 and σ2L=0.05.σL2=0.05. NOTE: This is a multi-part question. Once an answer is submitted, you will be unable to return to this part. Find P(T > 3).
You are cycling at a constant speed of 11.0 m/s on a level road. (b) How...
You are cycling at a constant speed of 11.0 m/s on a level road. (b) How much additional power is required to maintain this speed up a hill inclined at 3.00° with the horizontal? Assume the combined mass of you and your bicycle is 52.0 kg. If you need a value for the acceleration due to gravity, use g = 9.80 m/s2.
When a pendulum with a period of 2.00000 s in one location (g = 9.80 m/s2) is moved to a new location from one where the period is now 1.99869 s. What is the change in acceleration (in m/s2) due to gravity at its new location?
When a pendulum with a period of 2.00000 s in one location (g = 9.80 m/s) is moved to a new location from one where the period is now 1.99844 s. What is the change in acceleration (in m/s2) due to gravity at its new location?
When a pendulum with a period of 2.00000 s in one location (g = 9.80 m/s2) is moved to a new location from one where the period is now 1.99808 s. What is the change in acceleration in m/s) due to gravity at its new location? m/s²
(a) What is the length of a simple pendulum that oscillates with a period of 2.6 s on Earth, where the acceleration due to gravity is 9.80 m/s2, and on Mars, where the acceleration due to gravity is 3.70 m/s2? LE = LM = Enter a number. Im (b) What mass would you need to suspend from a spring with a force constant of 20 N/m in order for the mass-spring system to oscillate with a period of 2.6 s...
(a) What is the length of a simple pendulum that oscillates with a period of 3.0 s on Earth, where the acceleration due to gravity is 9.80 m/s2, and on Mars, where the acceleration due to gravity is 3.70 m/s2? LE = Lм %3 m (b) What mass would you need to suspend from a spring with a force constant of 20 N/m in order for the mass-spring system to oscillate with a period of 3.0 s on Earth, where...
13.11 A pendulum has a length of 4.8 m. a) At a location where the acceleration due to gravity is 9.80 m/s, what is the period of the pendulum? b) If the period of a pendulum is twice as much the value found in part a, what is the length?
I need help with these three
problems pls. show steps and formulas pls thanks.
13. A 119 g mass is attached to the end of an unstressed vertical spring (of constant 52.5 N/m) and then dropped. The acceleration of gravity is 9.8 m/s2 What is its maximum speed? Correct answer: 0.466573 m/s. 14. A(n) 60.3 g ball is dropped from a height of 53.7 cm above a spring of negligible mass. The ball compresses the spring to a maximum displacement...
Most questions answered within 3 hours.
-
Where is the error in this code sequence?
String s1 = "Hello";
String s2 = "ello";...
asked 10 months ago -
Financial data for Joel de Paris, Inc., for last year
follow:
Joel de Paris, Inc.
Balance...
asked 10 months ago -
Consider this reaction:
Al2(SO4)3 (aq)+ BaCl3
(aq) Al2Cl6 (aq)- +
3BaSO4(s) . What is the...
asked 10 months ago -
Suppose that Savneet is considering increasing her
recent random sample from 20 car rentals to 40...
asked 10 months ago -
Trucks arrive at an unloading terminal at an average rate of 120
per hour.
Trucks arrive...
asked 10 months ago -
Why are methanol and ethanol completely soluble in water while
octanol is not very little soluble....
asked 10 months ago -
A facilities manager at a university reads in a research report
that the mean amount of...
asked 10 months ago -
When the CuSO4 is rehydrated by adding water to the anhydrous
compound, is this an endothermic...
asked 10 months ago -
A ray of sunlight is passing from diamond into crown glass; the
angle of incidence is...
asked 10 months ago -
A block of mass 0.249 kg is placed on top of a light, vertical
spring of...
asked 10 months ago -
how do the kidneys compensate in the presences of acidosis
a) trigger hyperventilate
b) reserve acid...
asked 10 months ago -
Question 501 pts
The rental rate of capital to the firm increases. Which of the
following...
asked 10 months ago