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a) According to theory, the period T of a simple pendulum is T = 2π√L/g, where L is the length of the pendulum. IfL is measured as L = 1.40 ± 0.01 m,what is the predicted value of T?

b) Would you say that a measured value of T = 2.39 ± 0.01 s is consistent with the theoretical prediction of part (a)?

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The expression for the time period of the pendulum is, r長 Substitute, the values in the above equation. ˊ懾 T =2π 1.40 m 9.81 m/s -2.372 s The uncertainty in the time period is, r長 Taking log on both sides. In 7-In 2π+In :// _In Differentiating the above equation

2 1 AT 1 A T 21 2 1 (2.372 s) (0.01 m) 2 1.40 m 0.008471 Hence, the uncertainty in the time period is AT-(2.371+0.008471)s Since, the measured value is close enough with result in the part (a). Hence, the result is consistent with the measurement.

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