Question

write an equation of the line that passes through the given point and is parallel to the given line. Write the answer in a slope intercept form (0,4) 8y -48x=3
y= -1/6x + 6
y=-1/6x + 4
y=6x -4
y= -1/4x + 6
y=6x + 4

Answer 1

<font face="Tahoma" size=1.5> </pre><font size=4><b> Given: point (0,4); line 8y-48x=3 First, we transform the given line into slope-intercept form,{{{red(y=mx+b)}}}: {{{8y-48x=3}}} {{{8y=48x+3}}} ----> {{{cross(8)y/cross(8)=(48x+3)/8}}} {{{y=cross(48)6x/cross(8)+3/8}}} {{{red(y=6x+3/8)}}} ---> {{{slope=m=red(6)}}} *Remember, parallel lines have the same slope. So thru point (0,4) via slope-intercept form {{{4=(0)(6)+b}}} {{{b=4}}} So therefore it follows, {{{highlight(red(y=6x+4))}}},

Answer 2

{{{drawing(400,400,-6,6,-10,10,grid(1),graph(400,400,-6,6,-10,10,6x+3/8,6x+4),blue(circle(0,4,.12)))}}} ----> {{{red(8y-48x=3)}}};{{{green(y=6x+4)}}} Thank you, Jojo</font>