Question

organic- drawing product

Draw the product of the reaction between 3-phenylpropyne and NaNH2 in NH3, then D3O+, followed by D2, Pd/C.
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Answer #1

3-phenylpropyne in presence of NaNH2 in NH3 loses a proton and forms carbanion. NaNH2 NH3 3-phenylpropyne The carbanion forme

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Answer #2

NaNH NH D,0 DC D /Pd/C CD3 DC D2C

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