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GENETICS PROBLEMS

CCDD and ccdd individuals were crossed to each other, and the F1generation was backcrossed to ccdd parent. 903 CcDd, 897 ccdd, 98Ccdd, and 102 ccDd offspringresulted.
a) How far apart are the c and d loci?
b) What progeny would you expect to result from backcrossing the F1geeration from a CCdd * ccDD cross to ccdd?

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Answer #1
ø�mhÿ6 CCDDXccdd Parent generation

CcDdF1 generation

CcDdxccdd Test cross

CD

Cdcd gametes

cD

cd

CcDd903 Parentalcombinations

Ccdd897Ccdd 98
ccDd102 Recombinants

Recombination %=No. of Recombinants x100

TotalNo. of progeny

=200 x100 =10 %

2000

The distance betweenc &d=10 mapunits.b) CCXcc

ddDD

Cc

dD

CcDd

CcDd xccdd Test cross

C cCcc

õsahÿ6xk5 Dddd Gametes

ParentalC cDd

Combinationccdd 90%

Recombination ccDd

Ccdd 10%

awsu�/nxk58

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Power associated with
answered by: Shari
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Answer #2

In the given problem, two individuals with the genetic composition CCDD and ccdd are given. They were crossed, and the F1 generation was further backcrossed to the homozygous recessive parent, ccdd. The number of offsprings of the backcross along with their genetic composition is tabulated below.

image.png

The measure of tendency of two loci to undergo crossing over is defined as map units. Genes, that are located farther apart, have a higher probability of crossing over. The higher the crossing over frequency is, the genes are located farther apart on the chromosome. In short, the recombination frequency/ crossing over frequency gives the distance between the two genes.

Therefore, the frequency of recombinant genotype can be calculated as:image.pngimage.png


image.png

image.png

answered by: biology_frog
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