Since volume is constant
P/T = constant
P1/T1 = P2/T2
Also Pabs = Patm + Pgage
P1 = 95 + 190 = 285 kPa
P2 = 95 + 215 = 310 kPa
T1 = 273 + 25 = 298 K
=> T2 = (310 x 298) /285 = 324.14 K
= 324.14- 273 0C = 51.14 0C
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An automobile tire is filled to a gauge pressure of 185 kPa when
its temperature is 20°C. (Gauge pressure is the difference between
the actual pressure and atmospheric pressure.) After the car has
been driven at high speeds, the tire temperature increases to
57°C.
Please help with both parts of this problem. Thanks!
An automobile tire is filled to a gauge pressure of 185 kPa when its temperature is 20°C. (Gauge pressure is the difference between the actual pressure and...
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An automobile tire is inflated with air originally at 10.0°C and normal atmospheric pressure. During the process, the air is compressed to 27.0% of its original volume and the temperature is increased to 39.0°C. (a) What is the tire pressure in pascals? (b) After the car is driven at high speed, the tire's air temperature rises to 85.0°C and the tire's interior volume increases by 3.00%. What is the new tire pressure (absolute) in pascals?
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