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A chain of metal links with total mass M = 5 kg is coiled up in a tight ball on a...continues

A chain of metal links with total mass M = 5 kg is coiled up in a tight ball on a low-friction table. You pull on a link at one end of the chain with a constant forceF = 62 N. Eventually the chain straightens out to its full length L = 1 m, and you keep pulling until you have pulled your end of the chain a total distance d = 3.6 m.What is the increase in internal energy of the chain? [Hint: Compare the point particle system and the real system.]
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Answer #1

Fd/2 = 62*3.6/2 = 111.6 J

answered by: icabob
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