Using property of exponential modular -

Using this property, (61)610 mod 10 = (61 mod 10)610 = 1610
X = ((1610 + 1, 1671 - 1)671 + 1, (1610 + 1, 1671 - 1)610 - 1 )
X = ( (2, 0)671 + 1, (2, 0)610 - 1 )
Since gcd of(a, 0) = 0
X = (0671 + 1, 0610 - 1)
X = (1, -1)
That is X = gcd of 1 and -1
X = 1
Hence X can be represented using only a single bit
I have tried to explain it in very simple language and I hope that i have answered your question satisfactorily.Leave doubts in comment section if any.
Let (a, b) denote the greatest common divisor (ged) of the numbers a and b. Let x ((61610+1,6171-...
Let (a, b) denote the greatest common divisor (ged) of the numbers a and b. Let x ((61610+1,6171-1)61 +1, (61611,61671)610- 610 1,61 (a) Find X mod 10 (b) What is the minimum number of bits required to represent X?
Let (a, b) denote the greatest common divisor (ged) of the numbers a and b. Let x ((61610+1,6171-1)61 +1, (61611,61671)610- 610 1,61 (a) Find X mod 10 (b) What is the minimum number of bits required to represent X?
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88. Let D be an integral domain. (a) For a, b E D define a greatest common divisor of a and b. (b) For rE D denote (x)dr dE D.Prove that if (a) +(b)-...
Use R language to program
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