Question

each reactant from the following data. Show work, of co inspection) method (method of initial rates), calculate the order in course! Consult your text book if needed. wherex isonder(Rotel)=(C Ratel Rate2 log a og Con) Concentrato! ) ' 12/ = log( Order = use this: A Run Initial [A] Initial IB] 2 C of E 0.20M 0.20M 0.40M 0.20M 0.20M 0.20M 0.20M 0.60M Initial IC 0.20M 0.30M 0.30M 0.30M 2.42x106 M/min 2.44x106 M/min 9.67x106 M/min 7.23x10 M/min Remember, the idea is to pick two runs to compare where only the concentration of one reactant changes. Comparisons used Setup of calculation of order A:runs & B:runs & C: runs & (4pts) Write the overall rate equation using these calculated orders. rate k What is the overall order of the reaction? 4pts) Solve for rate constant (s).

Answer 1

a) Rate law Rate= 시시rerer Here, x is the order of the reaction wrt A, y ls the order of the reaction wrt B z is the order of the reaction w.r.t C Experiment 1: 2.42x10 M/min (.20) (0.20y (0.20 Experiment 2 2.44x10 Mmin (0.20)20 (0.30) Experiment 3:9.67x10 M/min-(0.40) (0.20 (030) Experiment 4:7.23x10 Mmin k (0.20) (0.60)' (0.30) 4 Divide the3 reaction by the2** to get the value of x 9.67x103 2.44x10 min (0.20) 4 (2) 22 (2) Hence, the order of the reacti on w.r.t Ais 2 Divi de the 4* reaction by the 2 to get the value of y 723x 10-6 Mtin 2.44 × 10- n (020) x" (0.60), (0 30f (0.20) - Hence, the order of the reaction w.r.t Bis 1 Divide the 2d reaction by the 1* to get the value of:z 244x10Mmm (020) 42x10 Mmin020y (020) (0.20) (0.30) 1=(15) Hence, the order of the reacti on w.rt Cis 0 Overall order 2+ 1+0 3 Therefore, the rate law is Rate = klafpferzkh"[B] b) Experiment 1 : 242 x 10-6 M/mın = k(0.20)"(0.20), (020)" Rate law Rate=k[A]2[BIcr Rate constant, Rate 2.42x10 Mimin (0.20 M) (0.20 M) (0.20 M) 2.42x106 M/min (0.20 M) (0.20 M) -3.025x10 Mmin -