Solution
D) At point E the charge on citric acid would be -2
E) Overall reaction is
3NAOH + CITRIC ACID -> 3H2O + C6H5O7(3-)
Now moles of NAOH at point E assuming the value of NAOH consumed is equal to 50ml from the graph.
Moles of NAOH = 50*0.1 = 5 milli moles
Limiting Reagent is NAOH, moles of CITRIC acid that will be consumed are 5/3
Moles of CITRIC ACID left will be (2-5/3)milli moles
Concentration of Citric acid = 1/3÷(70) = 1/210. , 70(20 citric acid + 50 NAOH) is the total volume.
From PKa3 we get Ka3 = 10^(-6.4) which is equal to
10^(-6.4) = [H+][C6H5O7(3-)]÷(1/210)
From here we get [H+] = 4.353*10^(-5)
And since PH = -log[H+]
So pH = 4.36
2. Soda has a pH between 3 and 4. Soda makers often add citric acid to give a tart taste to soda....
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Pls help on filling out Tritraion of a Polyprotic acid chart
Data from lab
Titration #1
Titration #2
Titration #3
mL base added
pH
mL base added
pH
mL base added
pH
1
0.7
1
0.7
1
0.7
2
1.1
2
1
2
0.9
3
1.5
3
1.4
3
1.3
4
1.7
4
1.6
4
1.5
5
1.9
5
1.8
5
1.7
6
2
6
2.1
6
2
7
2.2
7
2.2
7
2.2
8
2.4
8
2.3
8
2.2...
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