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4. Consider the rotational system shown below. For steel, G- 8.27 x 101° Nt/m2 and p 7800 kg/m, and for the fluid, μ = 0.309

44). 丁こ 5.ppu-m-Sec2 roe! rad

4. Consider the rotational system shown below. For steel, G- 8.27 x 101° Nt/m2 and p 7800 kg/m', and for the fluid, μ = 0.309 Nt-sec/m2. Given dı = 0.01m, d,-0.40m, Li-0.50m, L2 = 0.30m and h-0.2mm. a). find the torsional stiffiness K, of the shaft; b). find the moment of inertia J of the steel rotor; c). find the torsional damping constant B, ignoring the viscous effects of the oil on the left and right ends of the rotor. d), find the natural frequency, con and damping ratio ζ. Oil pa Steel slee
44). 丁こ 5.ppu-m-Sec2 roe! rad
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Answer #1

Given:

For steel-

Modulus of rigidity: G- 827.1010. n*

Density:ρ 7800kg

Fluid viscosity: μ-0.309 m2 n*

Diameter of shaft:d,0.01m

Diameter of rotor: d, 0.40m

Length of shaft: L. 0.50m

Length of rotor: 0.30m2

Thickness of oil layer: h = 0.2mm

a). Torsional stiffness Ks of the shaft

Torsional stiffness of the shaft is given by the relation

GJ K,우 ..(1)

J is the polar moment of inertia of the shaft given by the relation

zudl( 32

From equation (2) and (1) torsional stiffness

32L (3)

For shaft

media%2Ffbf%2Ffbfdf987-2fa4-4cc2-a6d1-72

media%2F9bf%2F9bf221dd-2e00-406a-a2f8-e7

On substituting values

K, = π·8232 10150001

media%2Feaf%2Feaf3e74d-8fde-41cb-b56c-ae

b). Moment of inertia of the rotor

Mass Moment of inertia for a cylindrical object is given by the relation

2 -mr ..(4)

media%2Fc14%2Fc149e1b9-72f6-490a-b0c3-f6 is the radius of rotor

media%2Fc9c%2Fc9c13a9c-82c8-49bb-b36d-50 is mass rotor

Mass of the rotor can be evaluated by product of volume and density

m=ρ*-*L ..(5) 4

From equation (4) and (5)

32

For rotor

media%2F675%2F675c0809-561b-4e54-adcf-1d

L-L,-0.30m

On substituting values

π * 7800 * 0.30 * 0.404 32

*g -5.88 in

c). Torsional damping constant B

The rotor is rotating in the surrounding environment of viscous oil, due to which damping effect(viscous force) will be generated., and this viscous force will cause resisting viscous torque.Viscous force is given by the following relation

media%2F58a%2F58aa568a-fb01-40de-95b9-08

media%2F0ba%2F0ba806a5-3c07-4c17-b4d3-a6 , is the area between rotor and stator

media%2Fbe5%2Fbe554785-334d-4ed9-be9e-72 is the viscosity of oil

media%2F829%2F82974137-75ad-4046-98e0-e5 is a relative velocity between rotor and stator

media%2F9c7%2F9c768759-4b58-4bdf-9b09-23 is the gap between rotor and stator

media%2Ffc1%2Ffc1e66c5-a82e-4f07-9616-dc is resisting torque due to viscous effect

media%2F5d5%2F5d5d07f5-2479-4f9b-b8c3-bb is rotor radius

media%2F89c%2F89cce832-6c99-4e84-acaf-ca is rotor angular velocity

On substituting in equation (6)

media%2Fda6%2Fda6a46c8-2f96-4179-998c-02

media%2F5f1%2F5f1f3332-c177-4de3-9fea-9e

Torsional damping constant is given by

Resisting torque T Angular velocityé

4h

For rotor

0.30m2

d, 0.40m

media%2F63e%2F63edd3fb-6c95-45f4-9c3e-11

On substituting values

π * 0.30 * 0.309 * 0.403 в= 4 2 10-4

N.m. s B- 23.298 raa

d). Natural frequency and damping coefficient

The natural frequency is given by the relation

media%2Fe66%2Fe6618130-2ab6-42c6-8c8a-9b

N.m K, - 162.38n rad is shaft stiffness

media%2Fd2f%2Fd2f35b29-e077-4c95-a29f-9d mass moment inertia of the rotor

On substituting values

530 162.38 5.88

media%2Fd27%2Fd2726d8f-a1d7-4d02-8a49-bf

Damping coefficient is given by the relation

media%2F6f5%2F6f59ac04-4f15-45bc-bb53-ec

B 23.298Nm. rad torsional damping coefficient

media%2Fb0f%2Fb0fad557-94e3-446f-88b9-33 is shaft stiffness

media%2Fd56%2Fd5620d17-af23-4c1c-a9eb-60 mass moment inertia of rotor

23.298 2V162.385.88

media%2Fafe%2Fafe1e232-d92c-4d15-940d-f7

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