Question 7 Working with buffers You need 100 ml of 120 mM phosphate buffer and you have two stock...
Question 5 Using stock solutions in a protocol: from volume to final concentration A DNA ligation reaction is carried out in a 25 μL reaction mix. This is a reaction carried out in cloning. You are going to do a number of these reactions so you decide to make up a larger volume of the reaction mixture, called a master mix. This saves on multiple repetitive pipetting and reduces errors. You have been given a protocol to make up 1...
Question 6 Using stock solutions to make up a solution: from final concentration to volume You need to digest a sample of DNA with a restriction enzyme. You will do this reaction later in the semester. The buffer for this reaction has a final concentration of 40 mM Tris, pH 7.5, 10 mM MgCl2 and 50 mM KCl. You have the following stock solutions: 0.5 M Tris, pH 7.5, 1 M MgCl2 and 2 M KCl. How would you make...
9,10,12
petermine the amounts/volumes of the chemicals needed to prepare the following solutions s 100 ml of O.1 N HC from concentrated (12.0 M) HO tyou will be asked to make this solution as practicel & 100 ml of L.0 M Tris pt-76 MW of Tris base is 121 g/mole 7. pH 7.6 is close to a neutral pH. When making 1.0 M Tris base, would you expect to or NaOH to adjust the pH to 7.67 to need HC...
Question 5 Using stock solutions in a protocol: from volume to final concentration A reverse transcription reaction is carried out in a 30 μL reaction mix. This type of reaction is carried out to convert RNA to complementary DNA. You are going to set up a number of these reactions so you decide to make up a larger volume of the reaction mixture, called a master mix. This saves on multiple repetitive pipetting and reduces errors. You have been given...
CALCULATIONS [2 points each] You are asked to perform a PCR experiment in the lab. However, in this experiment you must add each ingredient separately (unlike the "master-mix" we used in our own experiment). In this experiment, each PCR reaction tube contained the following ingredients added with a micropipetor... 10 HL of 5x Buffer 6 μ1 of 25 mM MgCl2 solution μL of 10 mM dNTP mix 1.5 μL oligonucleotide primer mix 0.5 HL Taq DNA Polymerase stock solution 28...
Question 23: (10 Marks) a) Given the stock concentration and desired final amount, or desired final concentration, of the following PCR components, calculate the volume of each you would add to a 25 μl PCR reaction mixture. b) You want to analyse the resultant PCR product by agarose electrophoresis. Calculate how much agarose you need to use to make up 50 ml of 1.5 % gel. How much of 5x concentrated loading buffer will you add to load the...
Question 2 1 pts You need to make a 500 mL buffer containing 35 mM NaCl and 50 mM Tris buffer. You already have a 5 M NaCl stock solution and a 1 M Tris stock solution. How much NaCl stock do you need (mL)?
You mix 3 solutions: 0.5 L of 10 mM Tris-HCl 1.5 mL of 1 M Tris-HCl 200 mL of NaCl at 1.2%(w/v) (MW: 58.44) What is the final concentration of NaCl, in mM?
The composition of a 10X restriction enzyme buffer us: 500mM Potassium Acetate; 200 mM Tris-acetate; 100mM Mg Acetate; 1 mg/ml BSA. a) If you set up a reaction with 25 uL final volume, what volume of 10X buffer would you add to obtain 1X? b) In reference to the above, what is the final concentration of BSA in the 25 uL reaction?
In our experiment, we will be using a portion of the phosphate buffer system that is based upon the following equilibrium: H2PO4- HPO42- + H+ pKa = 7.2 In this case, H2PO4- will act as the acid and HPO42- will act as the base. Materials: 1M NaOH: 40.01 g/L of solution 1M HCl: 83 mL conc. HCl/L of solution Potassium phosphate, dibasic, K2HPO4, MW= 174.18 Potassium phosphate, monobasic, KH2PO4 MW= 136.09 **I already preformed this lab, but I struggled a...