Question

1. Suppose you're back at home and you need to schedule an appointment with your internet provider to have someone come over and fix it. You have to be at home to let the person in. If you miss the serviceperson, you have (a) Although you're given an exact time (3:00pm), the company tells you that the serviceperson could show up Let X - the arrival time (in minutes) of tife serviceperson relative to the scheduled time. Then based on the to reschedule, and miss binging Netflix. at any random time between 20 minutes early and 20 minutes late. info you are given, you know that X is Uniformly distributed from -20 to 20 i. What is the probability the serviceperson shows up more than 19 minutes late? ii. You happen to be working that day; your goal is to try to leave in time to meet the serviceperson However, you don't want to take off too much time and just wait. On the other hand, if you get there too late, the serviceperson will have left and you'll have to reschedule the appointment. So you need to balance how much time you take off work with trying not miss the service person. To have 95% chance of meeting the service person (and have the same chance of being too early as too late), what time should you arrive at the house? (b) The company offers to send a different serviceperson instead. This other serviceperson's arrival time relative to the scheduled time is Normally distributed, with mean of zero minutes (i.e., exactly on time) and standard deviation of five minutes. i. What is the probability this second serviceperson shows up more than 9.8 minutes late? Hint Compute a Z score, and then use the Normal table to get the final answer (this is how you will do it on the exams) To have 95% chance of meeting the service person (and have the same chance of being too early as too late), what time should you arrive at the house? (c) The company says you can pick the serviceperson from (a) or the serviceperson from (b). Which do you pick, and why?

Answer 1

0 0,o25 7 cs Scanned witmin2. 0 : 08