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Problem 5. A Markov chain Xn, n probability matrix: 0 with states 1, 2, 3 has the following transition 0 1/3 2/3 1/2 0 1/2 If

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Answer #1

We first find the 3rd state transition matrix here as:

P = \begin{pmatrix} 1/2 & 1/3 &1/6 \\ 0 &1/3 & 2/3 \\ 1/2 &0 & 1/2 \end{pmatrix}

Now the product here is computed as:

P^3 = \begin{pmatrix} 0.3611 & 0.2037 & 0.4352 \\ 0.4444 &0.1481 & 0.4074 \\ 0.4167 &0.2222 & 0.3611 \end{pmatrix}

This is the required matrix here for 3rd transition state.

The probabilities for 2nd state here is computed as:

E(X_2)= \begin{pmatrix} 0.25 &0.5 &0.25 \end{pmatrix} \begin{pmatrix} 0.3611 & 0.2037 & 0.4352 \\ 0.4444 &0.1481 & 0.4074 \\ 0.4167 &0.2222 & 0.3611 \end{pmatrix} = \begin{pmatrix} 0.4167 &0.1806 &0.4028 \end{pmatrix}This is the required expected states for the 2nd state.

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