Question

Exact mass of sodium bicarbonate: 2.110g

Molar mass of sodium bicarbonate: 84.007 g/mol

Molar mass of sodium acetate: 82.034 g/mol

After you have recorded and any other glassware you have used. All waste can go down the sink. the mass of the beaker after the reaction, you may rinse out the beaker 10. CALCULATIONS: a) Rewrite the balanced chemical equation here Calculate the theoretical amount of sodium acetate that should be formed in the reaction (follow steps 1-3 below). b) Step 1: Calculate the number of moles of sodium bicarbonate actually used (use the exact mass of sodium bicarbonate you used in the reaction (step 1) and the molar mass from the prelab calculations). Show your work Number of moles of NaHCO, actually used Step 2: According to the balanced chemical equation, use the mole ratio of sodium acetate to sodium bicarbonate in the reaction to calculate the number of moles of sodium acetate that should form in the reaction. Show your work Moles of sodium acetate expectedThis is your theoretical yield of sodium acetate in MOLES. Step 3: Convert the number of moles of sodium acetate you just calculated into grams of sodium acetate using the molar mass from the prelab calculations. This is the theoretical yield of sodium acetate in GRAMS. Show your work Theoretical yield of sodium acetate:

Answer 1

(b) Mass of NaHCO₃ = 2.110g

Molar mass of sodium bicarbonate(NaHCO₃) = 84.007 g/mol

Moles of NaHCO₃ actually used = Mass / Molar mass = 2.110 g / (84.007 g/mol) = 0.0251 mol

Mole ratio of NaHCO₃ and NaCH₃COO is 1:1

Moles of NaHCO₃ actually used = Moles of NaCH₃COO expected = 0.0251mol

Molar mass of sodium acetate: 82.034 g/mol

Theoretical yield of sodium acetate (NaCH₃COO) = moles * molar mass = 0.0250 mol *82.034 g/mol = 2.06 g