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(a) To find out the rationalizable strategies , we need to eliminate those strategies which are never the best responses . Player 1 assumes player 2 is rational and player 2 assumes player 1 is rational . In the above question , there is no strategy for any player which is never the best response . T is the best response for C , M is the best response for l and B is the best response for R and you can find for the player 2 as well . Thus all the strategies are rationalizable .
(b) In the iterative elimination , we eliminate the strictly dominated strategies one by one . For player 2 , there is no strategy which is strictly dominated any strategy and for the player 1 as well . You can see in this way , for player 2 in strategy l and R , pay offs for player 2 by choosing L are ( 5 , 2 , 0) and for R (2,0,2) so L does not strictly dominate R . check for others ( C and R ) and ( L and C) and for the combinations of player 1 strategies as well .
(c) No strategies ruled out by the assumption of rationality .
(d) Pure strategy equilibrium : Those strategies which are best response of the other's player best response . In other words , no player has the incentive to deviate , if i say (T,l) is the pure strategy equilibrium , but player 1 has the incentive to deviate and choose m instead because 5 > 4 . Thus you can check all the strategies in this way and you will find there is only one pure strategy equilibrium and that is ( M , L )
1. Consider the following two-player game in strategic form: T4,5 3,0 0,2 M 5,2 2, 1,0 B0,02,84,2...
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