In the following code I give, everytime it will output ")".
Input :
((A+B)*((C-D)/(E^F)))
Expected output :
((A+B)*((C-D)/(E^F))) A+B*C-D/E^F
my output :
)
My code :
class Et:
def __init__(self , value):
self.value = value
self.left = None
self.right = None
def isOperator(c):
if (c == '+' or c == '-' or c == '*' or c == '/' or c == '^' ):
return True
else:
return False
def inorder(t):
if t is not None:
inorder(t.left)
print (t.value)
inorder(t.right)
def constructTree(postfix):
stack = []
for char in postfix :
if not isOperator(char):
t = Et(char)
stack.append(t)
else:
t = Et(char)
t1 = stack.pop()
t2 = stack.pop()
t.right = t1
t.left = t2
stack.append(t)
t = stack.pop()
return t
postfix = "((A+B)*((C-D)/(E^F)))"
r = constructTree(postfix)
inorder(r)Whatever code you have written does not take care of parenthesis like '(' or ')'. In order to get the correct output, you would need to take care of the parenthesis separately.
Only after you take care of them, you will get the desired output for the expression tree.
In the following code I give, everytime it will output ")". Input : ((A+B)*((C-D)/(E^F))) Expect...
In the following code I give, everytime it will output ")". Input : ((A+B)*((C-D)/(E^F))) Expected output : ((A+B)*((C-D)/(E^F))) A+B*C-D/E^F my output : ) My code : class Et: def __init__(self , value): self.value = value self.left = None self.right = None def isOperator(c): if (c == '+' or c == '-' or c == '*' or c == '/' or c == '^' ): return True else: return False def inorder(t): if t is not None: inorder(t.left) print (t.value) inorder(t.right)...
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Hi guys.
I need to return a method as an expression tree, it's currently
returning null.
public static ExpressionTree getExpressionTree(String
expression)
throws Exception {
char[] charArray = expression.toCharArray();
Node root = et.constructTree(charArray);
System.out.println("infix expression is");
et.inorder(root);
return et;
}
In the above method, et needs to have a value.
-- Take a look at the complete class below.
Kindly assist.
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