Please write a VBA program for 1b and for 2. I am lost. Thank you.

SOLUTION
program integration
! declaring the variable values
real results,simp13_res,simp38_res,a,b,error
real f
integer n
external f
results=0.0
n=0
a=0.0
b=1.0
error=0.0
write(*,*)achar(10),achar(10)
write(*,*)"Intergration of (x^n*e^(x-1)) by dx range of 0 to 1"
10 write(*,*)achar(10)
write(*,*)"Enter 0 to exit from the program"
write(*,*)"Enter n : "
read(*,'(i10)')n
!to exit
if(n==0)then
goto 20
end if
!factorial function calling
results=factorial(n) !calling the function factorial
write(*,*)achar(10),"Recursion Solution = ",results ! print the value of the function
!get simpson 1/3 solution
call simpson13(f,a,b,simp13_res,real(n))
write(*,*)achar(10),"Simpson 1/3 Solution= ",simp13_res
error=(results-simp13_res)*100/results
write(*,*)"Relative True Error in Simpson 1/3 (%) = ",abs(error)
error=0.0
!get simpson 3/8 solution
call simpson38(f,a,b,simp38_res,real(n))
write(*,*)achar(10),"Simpson 3/8 Solution = ",simp38_res
error=(results-simp38_res)*100/results
write(*,*)"Relative True Error in Simpson 3/8 (%) = ",abs(error)
!continue
goto 10
20 continue
end program integration
! end of the main program, functions are below which is used in this program
!recursive algorithm
recursive function factorial(n) result(results)
real results,first,x
integer n
x=1
first=1/exp(x)
if(n<=0) then
results = 0
return
else if(n==1) then
results=1/exp(x)
return
else
results=1-n*factorial(n-1)
return
end if
end function factorial
!simpson 1/3 algorithm
Subroutine simpson13(f,a,b,simp38_res,n)
real a,b,x,n,h,f,simp38_res
h=(b-a)/2.0
simp38_res=h*(f(a,n)+f(a+h,n)+f(b,n))/3.0
return
end Subroutine simpson13
!simpson 3/8 algorithm
Subroutine simpson38(f,a,b,simp13_res,n)
real a,b,x,n,h,f,simp13_res
h=(b-a)/3.0
simp13_res=h*3.0*(f(a,n)+3.0*f(a+h,n)+3.0*f(a+2*h,n)+f(b,n))/8.0
return
end Subroutine simpson38
!function to integrate
function f(x,n) result(res)
real x,n,res
res=(x**n)*exp(x-1)
return
end function f
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